Question

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Direction:- A balloon is moving upwards from the ground with a constant speed of 10m/s at a distance of 5m in front of a plane mirror of length 2m as shown in the figure.
A source 's' is placed symmetrically before the mirro. The plane mirror is placed at a height H=15m about the surface of ground.
Q) The maximum time interval during which a man inside the balloon can see the image of the source in the mirror is
Q) When the balloon is at height 17m from the ground, the man drops a stone from it then the maximum height attained by the stone will be (g=10m per second square

Answer 1

Answer:

just check the answer in the answer book

Answer 2

${\huge{\underline{\underline{\text{\color {plum}{❥Aղʂաҽɾ}}}}}} {\huge{\text{\color{plum}{:- }}}}$

velocity of the person=vp=10m/s

velocity of the mirror= vm= -20m/s(since it

is in opposite direction)

velocity of the image=velocity of the

person-velocity of the mirror

v of image=10+20=30 m/s