Question

The person went 30 m to the north and changed direction to 20 m to the east and then 30√2 m to the south-west. What is the initial position of the person's mate shift?​

Answer 1

Answer:

30m North

20m East

and the 30

2

SW can be rewritten as 30m in south and 30m in West

because south and west being at 90

0

result

in

30

2

+30

2

=30

2

so at last we have following data that in south X

S

=30m+north=30m+(−30m)=0,

negative becasue north is opposite to south.

and in West we have X

W

=30m+east=30m+(−20m)=10m

so the displacement is 10m due west

Explanation:

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Answer 2

Answer:

the displacement is 10m due west

Explanation:

30m North

20m East

and the 30√2 SW can be rewritten as 30m in south and 30m in West

because south and west being at 90°

result in √( 30^ 2 +30^ 2) =30 √2

so at last we have following data that in south X

S =30m+north=30m+(−30m)=0,

negative becasue north is opposite to south.

and in West we have X

W =30m+east=30m+(−20m)=10m

so the displacement is 10m due west