Question

the person who answer this question will be rewarded as brainliest

Answer 1

See the attachment for detailed solution.

Answer 2

Answer:

Step-by-step explanation:

If tan⁻¹ 3/4 = α

⇒tanα=3/4

Similarly tanβ=3/5

Now tan(α+β)= [tanα+tanβ]/1-tanα. tanβ = 27/11

α+β=tan⁻¹ (27/11) Let call it X

So tanX=27/11

Now, let tanY=8/19

Now, tan(X-Y)=[tanX-tanY]/1+tanX.tanY=[27/11-8/19]/[1+ 27/11 . 8/19]

=425/425=1

⇒tan⁻¹ 1= X-Y= tan⁻¹ (27/11) - tan⁻¹ (8/19)=α+β - tan⁻¹ (8/19) =  tan⁻¹ 3/4+ tan⁻¹ 3/5 - tan⁻¹ 8/19 = π/4 (since tan π/4 = 1)