Math, asked by asha12345, 10 months ago

the person who solve this is a real genius

Attachments:

Arey: sry to ask but I am trying a lot on this questions answer but it's a bit difficult

asha12345: it is one of in our question Paper

asha12345: its alright

Arey: oh my god it's so difficult

asha12345: thank u for your trouble

asha12345: bye.thanks once again

Arey: wait I will definitely give it's answer but you have to wait till evening . I will try my hard and best

Arey: it's okay

asha12345: ok

Arey: it's in my syllabus also and I am just like I'm best in Ap still I am unable to solve it

Answers

Answered by riteshgupta210papxse

A.P. can be 27,27,27.....

with a=27 and d=0

if we solve this by--

3rd term + 10th term = 5th term + 2nd term
a+2d + a+9d = a+4d + a+d
2a-2a = - 5d + 11d
0 = 6d ----------------(i)

now, we are given a+6d = 27
so, d = 27-a/6 ---------(1)

putting eq (1) in (i)
we get
a= 27 and d=0

Arey: sry but I think that it's wrong

riteshgupta210papxse: but here a2-a1 = a3-a2 and by this it can be said that the 27,27,27..... is in AP

Arey: if we take 0=6d then 0/6=d then if it's 0/6 then it's not possible because 0/6= not defined

riteshgupta210papxse: and its not compulsary that (d) can ≠ 0

riteshgupta210papxse: i will check about this and redo the question ....

Arey: okay

Arey: yup this is right

Arey: sry I think that d can't be equal to zero here

riteshgupta210papxse: ya the answer is right

Arey: yup I got to know now

Answered by Arey

solution told by my tution teacher
100% accurate

Attachments:

Arey: ??

Satya8585: hii

Previous Question

Next Question