The PH 0.1 M solution of an acid is 2.85 calculate ionization constant of an scid Ka plz give answer in easy way?
Answers
Answered by
2
Explanation:
pH of 0.08 mol dm-3 HOCl solution is 2.85. Calculate its ionisation constant. Ka=[H+]2[HA]=(1.413×10-3)20.08=2.4957×10-5.
if u think my answer is correct then mark me as a brainleist.
Similar questions