The ph at which a 0.01m al3+ solution is 99.99 precipitated is
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We have to find the pH at which 0.01M Al³⁺ solution is 99.99 % precipitated. Here Ksp of Al(OH)₃ is 1 × 10^-18 at 25°C.
Solution : dissociation reaction of Al(OH)₃ is ...
Al(OH)₃ (aq) ⇒Al³⁺ (aq) + 3OH¯ (aq)
0. S. 3S
so, to find solubility product :
Ksp = [Al³⁺][3OH¯]³
Ksp = S(3S)³ = 27S⁴ = 10^-18
⇒S⁴ = (100/27) × 10¯²⁰
⇒S = 1.387 × 10¯⁵
Now 3[OH¯] = 3S = 3 × 1.387 × 10¯⁵
= 4.161 × 10¯⁵
So, pOH = -log(4.161 × 10¯⁵) = 4.38
Therefore the pH of Solution = 14 - pOH = 14 - 4.38 = 9.62
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