Chemistry, asked by flower221, 4 months ago

The ph of 0.001 M aqueous solution of NAOH is​

Answers

Answered by shivanshipatel982
0

Answer:

NaOH is a strong electrolyte. It completely dissociates.

Thus [OH

]=[NaOH]=0.001 M.

pOH=−log[OH

+

]=−log10

−3

=3.0.

pH=14.0−pOH=14.0−3.0=11.0.

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