The ph of 0.001 M aqueous solution of NAOH is
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Answer:
NaOH is a strong electrolyte. It completely dissociates.
Thus [OH
−
]=[NaOH]=0.001 M.
pOH=−log[OH
+
]=−log10
−3
=3.0.
pH=14.0−pOH=14.0−3.0=11.0.
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