Science, asked by Abhishek158C, 5 months ago

The ph of 0.001N sodium hydroxide solution at 25C is

Answers

Answered by kumarprateek166

0

Answer:

pH=14−pOH

pOH of 0.001 N NaOH=−log[1×10^−3]=3

pH=14−3=11

Answered by manaswini65

0

Answer:

pH=14−pOH

pOH of 0.001 N NaOH=−log[1×10

−3

]=3

pH=14−3=11

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