The pH of 0.01 M NH4CN solution is (Ka(HCN) = 5x
10-10, Ko(NH3) = 2 x 10-5) (log 5 = 0.7, log 2 = 0.3)
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Answer:
pH=7+1/2 [pka-pkb]
pka=-log ka
=>-log (6.2×10^-10)
=>10-log (6.2)
=>10-0.79=9.21
pkb=-log kb
=>-log (1.6× 10^-5)
=> 5- log (1.6)
=>5-0.20=4.8
=>7+1/2[9.21-4.8]
=>7+1/2 [4.41]
=>7+2.205=9.205 ~9.21
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