Question

The pH of 0.02 M NH4Cl (aq) (pKb = 4.73) is equal to 1) 3.78 2) 4.73 3) 5.48 4) 7.00

Answer 1

Answer:

Explanation:

We know for salt hydrolysis

pH =1/2(pKw - pKb -logC )

    = 1/2 (14- 4.73 + 1.7)

     = 5.48