Question

The pH of 0.02 M NH4cl ( pkb = 4.73) is equal to

Answer 1

Answer:

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Answer 2

The pH of NH₄Cl is equal to 5.49

Explanation:

NH₄Cl is a strong salt which comprises of strong acid and weak base.

The pH is given by the formula:

pH = 7 - 1/2 [pkb + log c]

On substituting the values, we get,

pH = 7 - 1/2 [4.73 + log (0.02)]

pH = 7 - 1/2 [4.73 + log (2 × 10⁻²)]

pH = 7 - 1/2 [4.73 + log 2 + log 10⁻²]

pH = 7 - 1/2 [4.73 + log 2 + (-2 × log 10)]

pH = 7 - 1/2 [4.73 + 0.301 + (-2)]

pH = 7 - 1/2 [3.031]

pH = 7 - 1.51

∴ pH = 5.49