the pH of 0.043 m formic acid is 4.37 calculate its ionisation constant
plz answer
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1
Answer:
HCOOH+H
2
O→H
3
O
+
+HC
−
C
C(1−α) Cα Cα
K
a
=
c(1−α)
cα.cα
=
1−α
2
cα
2
α=14.5%=0.145
K
a
=
1−0.145
0.01(0.145)
2
K
a
=2.1×10
−4
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