Question

the ph of 1 litre solution containing equal moles of acetic acid and sodium acetate is (pka of acetic acid = 4.74)​

Answer 1

Answer:

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Answer 2

Given: Volume of solution = 1ltr

Moles of acetic acid = Mole of sodium acetate

To Find : pH of the solution

Solution:

- As given in the question moles of acetic acid and sodium acetate are same .

- So, Number of moles of acetic acid = number of moles of sodium acetate

=x moles.

- From the equation given below,

CH3COOH + NaoH --> CH3COONa + H2O

- The equation suggests that x moles of NaoH will react with x moles of acetic acid to form solution of acetic acid.

- So, 2x - x = x moles of sodium acetate (given in question)

- The formula of pH is given as:-

pH = pka + log(conjugate base/ weak acid)

- We can get conjugate base from sodium acetate and can get weak acid from acetic acid.

- So, pka = 4.74(given)

pH = 4.74 + log ( x/x)

- As log 1 = 1

So, pH = 4.74

- Hence, The answer is pH = 4.74