Chemistry, asked by jeni123, 1 year ago

The ph of 10^-13 mol dm-3 of an aqueous solution of H2SO4 is
A 3.0
B 2.7
C 2.0
D 1.5

Answers

Answered by KDRaika123
3
B) 2.7 .............

jeni123: how plz explain??
Answered by RomeliaThurston
11

Answer: The pH of the solution is 12.7

Explanation:

pH is defined as negative logarithm of hydrogen ion concentration. It is basically defined as the power of hydrogen ions in a solution.

The equation used to calculate pH of the solution is:

pH=-\log[H^+]

1 mole of sulfuric acid produces 2 moles of hydrogen ions.

We are given:

[H^+]=2\times 10^{-13}mol/dm^3=2\times 10^{-13}M

Putting values in above equation, we get:

pH=-\log(2\times 10^{-13})\\\\pH=12.7

Hence, the pH of the given H_2SO_4 solution is 12.7

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