Question

the pH of 10^-8 M of HCL ?

Answer 1

Answer:

tag me as brainleist

Explanation:

jajfjskskkfkf

Answer 2

Answer:

Explanation:

If in problem,

(i) the given concentration is ≥ 10^-5 M then it will be the concentration of acid only

(ii) the given concentration is between 10^-8 M and 10^-5 M then the concentration of acid will be = concentration of acid + concentration of water

(iii) the given concentration is far less than 10^-8 the it will be the concentration of water only

In this question, given concentration = 1 × 10^-8 so it follows step 2

i.e., concentration of acid = 10^-8 + 10^-7

= 10^-7 × 1.1

Then pH = -log(1.1×10^-7) =7 - log(1.1)

= 7 - 0.02 = 6.98

_____________________________

Additional information ❤

What is the pH of 10 9 M HCl?

Since its concentration is very low, you need to account for H+ ions of water as well. Hence total amount of H+ ions present will be 10^-9 + 10^-7 =1.01*10^-7. Hence pH would be -log(1.01*10^-7) = 6.99567.

_____________________________

What is the pH of a 1 * 10 8 m Naoh solution?

The pH of the solution is 7.

_____________________________

Hope it helps you ❤