Chemistry, asked by Anonymous, 11 months ago

The pH of 10^-8M NaOH is:

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Answers

Answered by puja200092
1

H2O <------> H+ + OH-

[H+]= [OH-]

Kw = [H+][OH-]= 1.0 x 10^-14

[OH-]= 1.0 x 10^-7

NaOH is a strong base NaOH => Na+ + OH-

[OH-] = 1 x 10^-8 M

total concentration OH- = 1 x 10^-7 + 1 x 10^-8 =1.1 x 10^-7 M

pOH = 6.96

pH = 14 - 6.96 =7.04


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