the ph of 5×10^-3 moles/L Ba (OH)2 solution is
Answers
Answered by
8
[OH-] = 10-²Molar
pOH = -log[OH-]
= 2
pH = 14-2
= 12
hope it helps you
@di
pOH = -log[OH-]
= 2
pH = 14-2
= 12
hope it helps you
@di
Answered by
1
(-Oh)=10°-14/H+. H+=10`-14-10`6=8
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