Question

the pH of a 0.005 M aqueous solution of sulphuric acid is approximately.​

Answer 1

Explanation:

0.005 Molar of aqueous solution sulphuric acid is present, Concentration of protons in acid is written as

[H + ]=0.005

pH=−log([H + ])=−log(0.005)=2.301

pH=2.301 approximately 2.

Answer 2

0.005 Molar of aqueous solution sulphuric acid is present, Concentration of protons in acid is written as

[H + ]=0.005

pH=−log([H + ])=−log(0.005)=2.301

pH=2.301 approximately 2.3

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