The ph of a 0.1 m solution of monosodium succinate (pka1 = 4.19 and pka2 = 5.57) is
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0.1m=1/100cm is the conversion sorry I couldn't help
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Answer:
pk1 +pk2 / 2 = and
4.19 + 5.57/ 2 = 4.82
Explanation:
when you take average of pk1 and pk2 ans would be appear
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