the pH of a .050 M boric acid solution is 5.28. What is the value of Ka?
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Answer:
Explanation:
we will find out ph by
ph =_log [concentration]
ph =_log [0.050]
ph = 1.30
pka + 10^-ph
pka = 0.05
ka = 10^-pka
ka = 0.891
so the answer is o.89
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