the ph of a 10^-10M NaOh solution is
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I think u have studied log
If yes this can help u to solve this
For NaOH
pOH = -log10[OH-]
or
pOH = -log10-10 = 10 log 10 = 10
so
pH = 14- pOH = 14-10 = 4
but since the concentration of naoh is very less ,the ph will be between 6 and 7
#neymarjr3
If yes this can help u to solve this
For NaOH
pOH = -log10[OH-]
or
pOH = -log10-10 = 10 log 10 = 10
so
pH = 14- pOH = 14-10 = 4
but since the concentration of naoh is very less ,the ph will be between 6 and 7
#neymarjr3
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