Question

The pH of a dibasic acid is 3.699. Its molarity
is
1) 2 x 104M
3) 2 x 10-3 M
32*10-3M
21 x 10-4M
A 1x 104 M​

Answer 1

Answer:

Normality equal to 10 to the power of -3.699 so molarity equal to 10 to the power of -3.699 divided by 2(dibasic acid)