the pH of a solution in which the[H^+]=0.01 is
Answers
Answered by
1
Answer:
pH=-log[H^+]
so by using formula
pH=-log[10^-2]=2
so ph =2 if solution is acidic and pOH=12 if basic(using ph+pOH=14
Answered by
0
Answer:
2 is it's pH...............
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