Question

the pH of a solution is 10 and that of another is 12 when equal volumes of these two are mixed the pH of the resulting solution is​

Answer 1

11 is the correct answer please

make it as brainliest

Answer 2

given

PH=10                                                             PH=12

-log[h+]=10                                                       [h+]=10^-12

[h-]=10^-10

N1V1+N2V2=NV

SO THE ANSWER IS 11