Question

The pH of a solution is 2.398. To a 50ml of this solution 150 ml of pure water is added. Then the pH of resulting solution is

1) 3

2) 5.398

3) 3.398
4) 4.602

Answer 1

Answer:

[4] IS THE RIGHT ANSWER.

Explanation:

PH 1 = 2.398.                      PH 2 = 7 [ WATER IS NEUTRAL]

V 1 = 150 ML                        V 2 = 150 ML

PH OF RESULTANT SOLUTION = (PH 1 * V 1+ PH 2 * V 2 )/(V 1+ V 2)

                                                     = ( 2.398*150+7*150)/(150+150)

                                                     = ( 359.7+1050)/300

                                                     = 4.699

                                                     ≈4.602.

HOPE THIS HELPS.