Question

The pH of a solution is 4.301. To 50 ml of this
solution 200 ml of water is added. Then the
pH of resulting solution is​

Answer 1

hence, pH of resulting solution is 5.

first find concentration of hydronium ions [H+] .

pH = -log[H+]

⇒4.301 = -log[H+]

⇒[H+] ≈ 5 × 10^-5 M

no of moles of H+ ions in solution = molarity × volume of solution

= 5 × 10^-5 × 50

= 2.5 × 10^-3 mol

now volume of solution after adding 200ml of water = 200 + 50 = 250ml

so, concentration of [H+] = 2.5 × 10^-3/250 = 1 × 10^-5 M

now pH = -log(1 × 10^-5)

= 5

hence, pH of resulting solution is 5.

also read similar questions :

What will be the pH of the resulting solution if to a 100 ml of HCl solution of pH = 1 , 900ml of disstilled water is ad...

https://brainly.in/question/1000050

A 50 mL solution of pH=1 is mixed with 50mL soltion of pH =2 .The pH of new mixture will be nearly (use log 5.5= 0.74)

https://brainly.in/question/2069988

Answer 2

Answer:

f the coconut chi and shield gameplay and shield the coconut from the