The pH of a solution obtained by mixing 100 ml of 0.2 M CH3COOH with 100ml of 0.2 M NaOH will be
(pKa for ch3cooh=4.74 and log 2=0.301)
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pH=1/2[pkw+pka-logc]
=1/2[14+4.74-log2*10^-1]
=1/2[18.74-0.7]
=1/2*18.04
=9.02
=1/2[14+4.74-log2*10^-1]
=1/2[18.74-0.7]
=1/2*18.04
=9.02
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