Question

The ph of a solution of HCL is 4 this shows that the majority of the solution is (a)4.0,0.4 0.0001 0.001

Answer 1

PH = - log [H+]

4 = - log [H+]

[H+] = 10^(-4)

[H+] = 0.0001

Here molarity of the solution will be equal to concentration of 1 × [H+] because there is only one H+ ion and one Cl- ion

0.0001M

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