Question

The Ph of a solution of HCL is 4. This shows that the molarity of the solution is :
(a) 4.0M (b) 0.4M (c) 0.0001M (d) 0.001M

Answer 1

c
...............................

Answer 2

It's answer would be c=. 0001M as
$ph = - log(h + ) \: \: from \: \: there \: we \: get \: (h + ) = \: \: 10 \: raise \: to \: power \: - 4 \: by \: putting \: in \: it \: m = n \div v \: we \: \: get \: the \: answer$