the ph of a solution of methanoic acid and sodium methanoate was 4.6. What was the ratio of methanoic acid concentration and HCOO ion concentration in the solution. Ka acid=1.6×10^-4
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Answer:
6.369
Explanation:
Solve this by using henderson hasselbalch equation
4.6=3.795+log([A⁻]/[HA])
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