The pH of a tomato juice is 2. Calculate[3
+] and [
−]
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Answer:
[H+] =10^-2
[OH-]=10^-12
Explanation:
pH=-log[H+]
2=-log[H+]
log[H+]=-2
[H+]=antilog(-2)
[H+]=10^-2
[H+][OH-]=10^-14
[OH-]=(10^-14)/[H+]
[OH-]=(10^-14)/(10^-2)
[OH-]=10^-12
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