Chemistry, asked by yashrathore3696, 6 months ago

The pH of lemon juice at 298 k is 2.0.calculate [H3O+] and [ OH- ] in it's solution

Answers

Answered by sima77081

0

Explanation:

ph:=- log[H3o+]

2.3= -log [H3o+]

antilog (-2.32)=[H3O+]

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