Question

the pH of mixture of 0.01 M Hcl and 0.1M of acetic acid is

Answer 1

0.01M Hcl and 0.1M CH3COOH is Given  

So H+  in HCl will be 10-2 and also in CH​3COOH is 10-1  

Let volume of HCl and CH3COOH be V  

According to formula H+ =N1V1 + N2V2/ total volume  

here N1=1* 10-2 and N2=1*10-1  

so by putting in formula,

H+= 10-2* V +10-1* V/2V

H​+=11*10-2/2

H+= 5.5 * 10-2

So, PH= - log[H+]  

Therefore  PH= - log[5.5 * 10-2]

PH=2- log 5.5

PH=2-0.74  

PH=1.26