Question

The pH of saturated aqueous solution of BaOH2is 10. If the Kspof BaOH2is5×10−13, then the concentration of Ba2+ions in the solutions is​

Answer 1

Answer:

We know that,

        pH+pOH=14

         10+pOH=14

                pOH=4

      pOH=-log[OH-]

           4=-log[OH-]

          [OH-]=1 × 10^-4

BaOH2⇄Ba2+ + 2OH-

   Ksp=[Ba2+]×[OH-]²

 5×10-13=[Ba2+]×[1×10-4]²

∴[Ba2+]=5×10-5