Question

the pH of solution change from 425 the change in H + will be. (a) 5 times (b) 10 times (c) 10-1 times (d) no change​

Answer 1

Correct Question

The pH of solution change from 4 to 5. Then the change in H⁺ will be.

(a) 5 times

(b) 10 times

(c) 10⁻¹ times

(d) no change​

$\bigstar$ Answer $\bigstar$

$\checkmark$ Given:

⇒ The pH of solution change from 4 to 5

$\checkmark$ To Find:

⇒ The change in H⁺

$\checkmark$ Solution:

We know that,

$\red{\boxed{\boxed{\rm pH=-log[H]^{+}}}}$

Given that,

The pH of solution change from 4 to 5

Therefore,

→ Initial pH = 4

→ Final pH = 5

Hence,

⇒ When pH = 4

$\orange{\rm \implies [H^{+}]=10^{-pH}}$

$\orange{\rm \implies [H^{+}]=10^{-4}}$

⇒ When pH = 5

$\purple{\rm \implies [H^{+}]=10^{-pH}}$

$\purple{\rm \implies [H^{+}]=10^{-5}}$

Therefore,

Change in Hydrogen ion [H⁺] concentration will be

$\blue{\implies \rm Change \ in \ [H^{+}]=\dfrac{10^{-4}}{10^{-5}}}$

$\blue{\implies \rm Change \ in \ [H^{+}]=10^{-4+5}}$

$\blue{\implies \rm Change \ in \ [H^{+}]=10^{1}}$

$\blue{\implies \rm Change \ in \ [H^{+}]=10}$

Hence,

Change in Hydrogen ion

[H⁺] concentration will be 10

So,

$\red{\large{\bold{\dagger}}}$ The change in H⁺ is 10 times $\red{\large{\bold{\dagger}}}$

Therefore,

$\checkmark$ Option (b) is correct $\checkmark$