Question

the ph of solution is 2.its ph is to be changed to 4 then H+ion concentration, in comparison to original solution, will be​

Answer 1

Answer:

Concenteration of H+ ion in solution having pH 2 = 10^-2.

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And concenteration of H+ ion in solution having pH 4 is 10^-4.

Answer 2

$H^+$ ion concentration, in comparison to original solution, will be​ $\frac{1}{100}$

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

$pH=-\log [H^+]$

1. Solution with pH of 2

$2=-log[H^+]$

$[H^+_A]=10^{-2}$

2. Solution with pH of 4

$4=-log[H^+]$

$[H^+_B]=10^{-4}$

Thus Solution A with low pH has higher concentration.

$\frac{H^+_B}{H^+_A}=\frac{10^{-4}}{10^{-2}}=10^{-2}=\frac{1}{100}$

$[H^+_B]=\frac{1}{100}\times [H^+_A]$

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