Question

The ph of the solution is 3.Its (oh)concentration is

Answer 1

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• [OH-] = 10-¹¹

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• We know that, pH + pOH =14

=====> pOH= 14 - pH

GIVEN → pH= 3

substitute 3 in the place of pH

=====>pOH = 14- 3= 11

required answer →→ [OH-] concentration

we know the value of pOH,

===> [OH-] = 10^-pOH

===>[OH-] = 10-11 (pOH=11)

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