Question

the ph of tomato juice is 4.4 calculate oh and h3o​

Answer 1

$\bf\red{Answer}$

PH = 4.4

$PH = log[H^{+}]= log[H_{3}O^{+}]$

$-log[H_{3}O^{+}]=-4.4$

$[H_{3}O^{+}]= Antilog(-4.4)$

$[H_{3}O^{+}]=3.981×10^{-5}$

$OH^{-}=14-3.981×10^{-5}$

$= 13.99$