Question

the ph ofa 0.010M Naohsolution is nearest to​

Answer 1

Hey brainly user

Here is your answer

$h {}^{ + } = 0.010$

$h {}^{ + } = 1 \times 10 {}^{ - 3}$

P[H]=-log H+

P[H]=-log 1×10^-3

P[H]= 3log -log1

P[H]=3

if you liked my answer then don't forget to mark as brainliest answer