Question

The pH value for 1/1000 N-KOH solution is :
(a) 3
(b) 10⁻¹¹
(c) 1
(d) 11

Answer 1

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✏ Option [D ] is Correct

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Answer 2

hi friends.....

your answer is (d) 11

explanation......

pH=11.

We know that due to the autoprotolysis reaction of water,
[H3O+][HO−]=10−14⋅mol⋅L−1 under STANDARD conditions…

We take logs of BOTH sides…and we get the expression…

14=−log10[H3O+]−log10[HO−]

Equivalently…14=pH+pOH…because pH=−log10[H3O+] etc…you know the drill…

Now here we are given that [KOH(aq)]=[HO−]=10−3⋅mol⋅L−1.

And thus pOH=−log1010−3=−(−3)=+3…and so pH=14−3=11

hope it helps..........