Question

The ph value of the incoming water is 7.2 and outgoing water is 8.4 assuming alinear variation of ph wiyh time determine average ph

Answer 1

Explanation:

pOH of I-solution= 14–7.2= 6.8

The pOH of II- Solution= 14- 8.4= 5.6

[OH-] Conc.of I-solution= 10^-6.8 =1.585x10^-7

[OH-] Conc. of II-solution=10^-5.6 =2.512x10^-6

Average conc. of both solutions = [(1.585x10^-7)+ (2.512 x 10^-6) ] ÷ 2

=1.3352 x 10^-6 M.

pOH of the mixture= - log(1.3352 x 10^-6)

= 5.874.

So pH= 14.000 - 5.874

= 8.126