Physics, asked by kisanasonekar, 11 months ago

the phase difference between displacement and acceleration of a particle performing simple harmonic motion is​

Answers

Answered by Tanya000
0

Answer:pi

Explanation:

Answered by marathesadhana44
0

Answer:

π radian or 180

Explanation:

The phase change of a particle performing SHM between successive passage through the mean position is given below-

  • Simple harmonic motion is a type of periodic motion where the restoring force on the moving object is directly proportional to the magnitude of the object's displacement and acts towards the object's equilibrium position
  • Displacement of the particle executing SHM is given by x = ACoswt (Where x is the displacement, A is the amplitude, w is the angular frequency, t is the time.)

Differentiating it with respect to time we get v = dx/dt (Where v is the velocity)

= -Awsinwt

Differentiating it again with respect to time we get acceleration as a = dv/dt (Where a is the acceleration.)

a=-Aw²Coswt

a=Aw C os(wt+n)

The difference between the displacement and acceleration is 180°.

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