Question

. The phase difference between the current through the resistance and voltage across the resistance in a series LCR circuit is

Answer 1

In an L-C-R (Inductor-Capacitor-Resistor) circuit, the phasor diagram is drawn taking the inductor, capacitor and the resistor in series.

Clearly, there is no phase difference between the voltage across the resistor and current flowing through the circuit and it follows simply the equation V=iR (V and i in RMS values)

There is a phase difference between the voltage across the resistor and the resultant voltage, which is equal to θ = $tan^{-1} (\frac{ V_{L}-V_{C} }{V_{R}} )$

REQUIRED ANSWER : 0°

Answer 2

Answer:

Explanation:

In an L-C-R (Inductor-Capacitor-Resistor) circuit, the phasor diagram is drawn taking the inductor, capacitor and the resistor in series.

Clearly, there is no phase difference between the voltage across the resistor and current flowing through the circuit and it follows simply the equation V=iR (V and i in RMS values)

There is a phase difference between the voltage across the resistor and the resultant voltage, which is equal to θ =  

REQUIRED ANSWER : 0°