The phase difference between two waves, represented byy₁ = 10⁻⁶ sin{100 t + (x/50) + 0.5} my₂ = 10⁻⁶ cos{100 t + (x/50)} mwhere x is expressed in metres and t is expressed in seconds, is approximately(a) 1.5 radians(b) 1.07 radians(c) 2.07 radians(d) 0.5 radians
Answers
Answered by
1
it's answer should be option B because phase difference between them is π/3
Similar questions