Question

The phase trajectory in phase space of bullet of units mass fired straight upwards with initial speed of 392 m/s is

Answer 1

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Given:

Mass of Bullet = 10g

Velocity of Bullet = 100 m/s

Mass of gun = 500 g (0.5kg)

To Find:

Momentum of Bullet?

Velocity of Gun?

Momentum of Gun?

Solution:

❖Momentum of Bullet;

Mass of bullet is 10g

=> 1kg = 1000 g

=> kg = 10/1000

=> kg = 0.01 kg

Momentum = Mass

★

Momentum=Mass×Velocity

Where

p = Momentum

m = Mass

v = Velocity

➙ p = m × v

➙ p = 0.01 × 100

➙ p = 1 kg.m/s

Momentum of bullet is 1kg.m/s.

★

Momentum

(Bullet)

=Momentum

(Gun)

After substituting values,

➙ Momentum (bullet) = Momentum (Gun)

➙ m × v = m × v

➙ 0.01 × 100 = 0.5 × v

➙ 1/0.5 = v

➙ v = 2 m/s

Velocity of Gun is 2 m/s.

❖Momentum of Gun;

★

Momentum=Mass×Velocity

➙ p = m × v

➙ p = 0.5 × 2

➙ p = 1 kg.m/s

Hence,

The Momentum of gun is 1 kg.m/s.

_____________________

Explanation:

100% correct answer

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