Biology, asked by Czane, 5 months ago

The phosphoanhydride bond that links 2 phosphate groups in ATP in a high-energy linkage has a ∆G° of -7.3 kcla/mole (-30 kJ/mole). Hydrolysis of this bond liberates from 11 and 13 kcal/mole of usable energy.

How can this be?
Why do you think anrange of energies are given, rather than a precise number for ∆G° ?​

Answers

Answered by Anonymous
10

Answer:

Under standard conditions, enzymatic hydrolysis of the terminal high-energy β–γ and α–β phosphoanhydride bonds . so this can be . and anrange of energies are given, rather than a precise number for ∆G° because to be the measurer for spontaneity of a reaction is because it does not depend whether the reaction was exo- or endothermic.

hope it helps you

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