the photoelectric cut off voltage in a certain experiment is 1.5 volt what is the maximum kinetic energy of the photoelectrons emitted
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1.5×1.6×10^-19 joule
vighnesh557:
Can u tell the steps also
energy=charge×potential
I want to get all ships in this problem so that I can submit in our class please its urgent
can you send all the steps for it I want to submit a class teacher its urgent please
world step by step please
As pot diff=work/charge=energy /charge so energy =potential×charge =1.5× charge of electron=......
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