Physics, asked by Abhi83999, 11 months ago

the photoelectric cutt off voltage on a certain experiment is 1.5V. What is the maximum kinetic energy of photoelectrons emitted?​

Answers

Answered by Anonymous
0

\huge\mathbb\blue{BONJOUR,}

\huge\mathfrak{Answer:}

The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted? Therefore, the maximum kinetic energy of the photoelectrons emitted in the given experiment is 2.4 × 10−19 J.

<font color ="purple"><marquee behavior ="alternate"> ~♥~~♥~Hope It Helps~♥~~♥~</font color ="purple "></marquee behavior="alternate">

\huge\mathfrak{Regards}

\huge\mathbb\red{Aaravxxx}

Similar questions