Question

The photoelectric threshold frequency of a metal is V when light of frequency 4V is incident on the metal, the maximum kinetic energy of the emitted photoelectrons is

A) 5/2hv
B)3v
C)4hv
D)5hv

Answer 1

The maximum kinetic energy of the emitted photo electrons is 3hV .

Given :

Photoelectric threshold frequency of a metal is V .

Frequency of incident light is 4V .

We need to find the maximum kinetic energy of the emitted photo electrons .

We know , maximum kinetic energy is given as :

$K.E_{max}=hv-hv_o$

Here $v$ and $v_o$ are frequency of incident light and photoelectric threshold frequency of a metal respectively .

Putting all given values , we get :

$K.E_{max}=h(4V)-(hV)\\\\K.E_{max}=3hV$

Hence , this is required solution .

Learn More :

Photoelectric Effect

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