the photoelectric threshold wavelength for a certain metal is 4000A the max energy of the ejected photoelectrons by the radiation of 2000A is
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Answered by
2
Answer:
1.0ev
Explanation:
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ANSWER
If the maximu kinetic energy of photoelectron emitted from the surface of a metal is E
k
and W is work function of the metal, the from Einstein photoelectric equation we have
E
k
=hv−W
where, hv is the energy of the photon absorbed the electron in the metal.
Also v=
λ
c
=
wavelength
velocity
=E
k
=
λ
hc
−
λ
0
hc
=hc(
λ
1
−
λ
0
1
)
Given, λ=3×10
−7
m,
λ
0
=4×10
−7
m.
∴E
k
=.6×10
−34
×3×10
8
×(
3×10
−7
1
−
4×10
−7
1
)
=
12×1.6×10
−19
19.8×10−19
eV
=1.03≈1eV.
Answered by
3
Answer:
10. 9 ev
Explanation:
is the right answer to your q............uestion.
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